3x^3-4x^2-12s+16=0

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Solution for 3x^3-4x^2-12s+16=0 equation:


Simplifying
3x3 + -4x2 + -12s + 16 = 0

Reorder the terms:
16 + -12s + -4x2 + 3x3 = 0

Solving
16 + -12s + -4x2 + 3x3 = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -12s + -4x2 + -16 + 3x3 = 0 + -16

Reorder the terms:
16 + -16 + -12s + -4x2 + 3x3 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -12s + -4x2 + 3x3 = 0 + -16
-12s + -4x2 + 3x3 = 0 + -16

Combine like terms: 0 + -16 = -16
-12s + -4x2 + 3x3 = -16

Add '4x2' to each side of the equation.
-12s + -4x2 + 4x2 + 3x3 = -16 + 4x2

Combine like terms: -4x2 + 4x2 = 0
-12s + 0 + 3x3 = -16 + 4x2
-12s + 3x3 = -16 + 4x2

Add '-3x3' to each side of the equation.
-12s + 3x3 + -3x3 = -16 + 4x2 + -3x3

Combine like terms: 3x3 + -3x3 = 0
-12s + 0 = -16 + 4x2 + -3x3
-12s = -16 + 4x2 + -3x3

Divide each side by '-12'.
s = 1.333333333 + -0.3333333333x2 + 0.25x3

Simplifying
s = 1.333333333 + -0.3333333333x2 + 0.25x3

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